4t^2+4t=80

Solution for 4t^2+4t=80 equation:

4t^2+4t=80

We move all terms to the left:

4t^2+4t-(80)=0

a = 4; b = 4; c = -80;
Δ = b2-4ac
Δ = 42-4·4·(-80)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-36}{2*4}=\frac{-40}{8}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+36}{2*4}=\frac{32}{8}
=4
$